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## Homework Statement

A truck is traveling down the road at 60 mph, and begins to decelerate at a rate of 0.8 g.

I'd like to find the total distance it takes the truck to stop, and come up with a formula for the velocity as a function of displacement from the original braking point.

## Homework Equations

I think that the relevant equation is v

^{2}= 2a(s

_{2}-s

_{1})+v

_{1}

^{2}

## The Attempt at a Solution

Well, I know the truck is traveling at 88 fps, and slowing at a rate of 0.8 * 32fps

^{2}, so it will take

88 fps / (32.2 fps

^{2}* 0.8 g) * 44 fps = 150 feet to stop

But when I plug those numbers into the above equation, I get

v

_{2}= (2 * (0.8 * 32.2 * 60 / 88) * (-x) + (60)

^{2})

^{0.5}

That has the right y-intercept (65 mph), but the wrong x-intercept, around 104'

If I change the "2" on the right side of the equation to 1.38, it looks right, but I can't work out why it would be 1.38 instead of two.

Argh! Any help much appreciated!